On Aug 13, 6:06 am, Arnold <ericarno...@yahoo.com> wrote:
> Hi Mike,
> Your re-wording of my problem is correct. Grades are listed in cols.
> AO, AP, AQ, AR... with total possible in row 10 of each col. and
> students down col. A.
>
> Your formula works if there is there is a numeric value in AO13 or
> AP13. However, it shows #DIV/0! if AO13 is left null.
>
> I tried to redo some of the absolute / relative references to account
> for the fact that I only have col. AO right now (through time, AP, AQ,
> AR, etc. will be added; we don't know the end of the range though).
> However, I got the same #DIV/0! result.
>
> =SUMIF($AO13:AO13,">-.1",$AO13:AO13)/SUMIF($AO13:AO13,">-.1",$AO$10:AO
> $10)*100
>
> I think we're close. Any other suggestions? I, and other teachers,
> appreciate your help.
> Arnold
you could put a simple if then to check if a the denominator of the
equation will be zero, if so return "N/A", otherwise return the score
=IF(SUMIF($AO$13:$AR$13,">-1",$AO$10:$AR$10)=0,"N/A",SUMIF($AO
$13:$AR$13,">-.1",$AO$13:$AR$13)/SUMIF($AO$13:$AR$13,">-1",$AO$10:$AR
$10))
the first part of the equation test the sum if of the total posible
score based on if there is a student score or not. If the total
score, student score or both are blank the sumif will result in 0 and
the logic test will return true. if the total points and the student
have a score >-1 the equation will return the sum of the student
scores / total posible. you can substitue any column for AR. the
formula will only use the data if a total posible is entered.
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