Cyde Weys wrote:
> Christiaan van Bladel wrote:
>
>> Cyde Weys schreef:
>>
>>> I blew the fuse on my Radio Shack multimeter recently. I was
>>> testing the current across a 9V battery.
>>
>>
>> When you say "across" , do you mean that you connected the black
>> lead to the minus of the battery and the red lead to the plus of the
>> battery? If so, this is not the correct way te messure the current,
>> how ever it is the correct way to messure the voltage. Mistakes are
>> easely made.
>
> So what is the correct way to measure current?
>
>>> Anyway, my multimeter has the following options on it: 15, 150,
>>> 1000 DCV, RX 1K(Ohms), OFF, 150mA DC, 1000, 150, 15 ACV.
>>
>>
>> The way i read this, your meter only supports current messuring
>> up to 150mA DC. So 315mA from the battery is enough to blow the fuse.
>> The rest of the ranges are used for resistor messuring and voltage AC
>> and DC voltages
>
> Yeah, that must be what I did. I must've had it in current measuring
> and put it across the 9V battery and fried the fuse. Oh well. What
> is the mA option for? Obviously it doesn't work directly across
> battery leads ... is it for putting into a circuit that has
> resistance? I.e. you could measure the current being drawn by an
> LED, but it won't work if you just put it across the battery?
Imagine a simple circuit with a battery source and a resistor. Each leg of
the resistor is connected to the battery; one to the +ve side, one to
the -ve side. To measure voltage across (in parallel) the resistor aka load,
place the meter in DC voltage mode. Place the black probe to the the -ve
side of the load, red probe to the +ve side. Take a reading. That's the
procedure for voltage.
A voltmeter can be thought of as a resistor with an infinitely high internal
resistance.
Imagine the same circuit, a battery and a resistor. To measure current, the
ammeter must be in _series_ with the load. Set the meter to measure DC
current. Current will flow _through_ the meter, as if it is another resistor
in the circuit. In fact, it will be just that, a very low resistance. Open
the circuit by lifting the -ve leg. Connect the red probe to the now open
leg of the resistor. Connect the black probe to the -ve terminal of the
battery. The circuit is now closed. Current will flow. Take the current
measurement.
Voltage|in parallel|voltmeter like a 10G Ohm resistor.
Current|in series|ammeter is like a .1 Ohm resistor.
|