Sorry for the delay in responding (I don't visit the newsgroups that often
anymore). Here is a link to the thread I mentioned...
http://social.answers.microsoft.com/...7-d22f6dca8a92
but to save you the time of searching it out, here is what I responded over
there...
Consider this...
Dim xRange As Range, yRange As Range, NewRowBeginning As Long
NewRowBeginning = 5
Set xRange = Range("C1

10")
Set yRange = Intersect(xRange, Range(NewRowBeginning & ":" & Rows.Count))
'
' Test to see if the range came out right
'
If Not yRange Is Nothing Then
MsgBox yRange.Address(0, 0)
Else
MsgBox "The specified new row beginning is located below the specified
range"
End If
--
Rick Rothstein (MVP - Excel)
"CompleteNewb" <(E-Mail Removed)> wrote in message
news:i9f0om$dpr$(E-Mail Removed)...
> Can you guys either copy the response here or give a link to the post in
> the other newsgroup? I searched the Microsoft forums for both you guys as
> authors, as well as looking for the subject line and the range reference
> text, and found nothing.
>
> And this seems like a question that's totally related to things I'm having
> issues with now.
>
> Thanks.
>
> "Terry" <(E-Mail Removed)> wrote in message
> news:abfa0efc-5d3d-47fe-a27f-(E-Mail Removed)...
> On Oct 14, 11:40 pm, "Rick Rothstein"
> <rick.newsNO.S...@NO.SPAMverizon.net> wrote:
>> I just posted a response to this same question over in the Microsoft
>> forum
>> (I'm assuming you posted it there as the ranges look familiar).
>>
>> --
>> Rick Rothstein (MVP - Excel)
>>
>> "Terry" <webtour...@gmail.com> wrote in message
>>
>> news:565ed3ac-e74d-457c-bd6c-(E-Mail Removed)...
>>
>>
>>
>> > Given a Range object (e.g: set xRange = Range("C1
10") )
>>
>> > And given xRow = 5 , which stands for Row 5 (absolute Row index)
>>
>> > How to define a range "yRange" based on "xRange" so that yRange is
>> > Range("C5
10") ?
>
>
>
> yes thanks