Say I have three DateTime variables:

DateTime A;
DateTime B;
DateTime C;

How can I assign to C just the date part of A and just the time part of B?

Something like this...

C = A.Date + B.TimeOfDay;

Except that isn't it.

Patrick B <(E-Mail Removed)> wrote:
> Say I have three DateTime variables:
>
> DateTime A;
> DateTime B;
> DateTime C;
>
> How can I assign to C just the date part of A and just the time part of B?
>
> Something like this...
>
> C = A.Date + B.TimeOfDay;
>
> Except that isn't it.

I ended up writing a utility method which did something like this -
it's not hard to write once and then use repeatedly. Basically use the
form of the DateTime constructor which takes everything you want, and
take some parts from A and some parts from B.

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

Hi,

Another solution could be take the data part of A

a.Date

and the time components of B

b.Second , b.Hour , b.Minute

That should work

Cheers,

--
Ignacio Machin,
ignacio.machin AT dot.state.fl.us
Florida Department Of Transportation



"Jon Skeet [C# MVP]" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Patrick B <(E-Mail Removed)> wrote:
>> Say I have three DateTime variables:
>>
>> DateTime A;
>> DateTime B;
>> DateTime C;
>>
>> How can I assign to C just the date part of A and just the time part of
>> B?
>>
>> Something like this...
>>
>> C = A.Date + B.TimeOfDay;
>>
>> Except that isn't it.
>
> I ended up writing a utility method which did something like this -
> it's not hard to write once and then use repeatedly. Basically use the
> form of the DateTime constructor which takes everything you want, and
> take some parts from A and some parts from B.
>
> --
> Jon Skeet - <(E-Mail Removed)>
> http://www.pobox.com/~skeet
> If replying to the group, please do not mail me too

Or, if we wanted to be really nifty:

// Get the date and time.
DateTime now = DateTime.Now();

// Get the date portion, and the time.
DateTime date = now.Date;
TimeSpan time = now.TimeOfDay;

Hope this helps.

--
- Nicholas Paldino [.NET/C# MVP]
- (E-Mail Removed)

"Ignacio Machin ( .NET/ C# MVP )" <ignacio.machin AT dot.state.fl.us> wrote
in message news:%(E-Mail Removed)...
> Hi,
>
> Another solution could be take the data part of A
>
> a.Date
>
> and the time components of B
>
> b.Second , b.Hour , b.Minute
>
> That should work
>
> Cheers,
>
> --
> Ignacio Machin,
> ignacio.machin AT dot.state.fl.us
> Florida Department Of Transportation
>
>
>
> "Jon Skeet [C# MVP]" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
>> Patrick B <(E-Mail Removed)> wrote:
>>> Say I have three DateTime variables:
>>>
>>> DateTime A;
>>> DateTime B;
>>> DateTime C;
>>>
>>> How can I assign to C just the date part of A and just the time part of
>>> B?
>>>
>>> Something like this...
>>>
>>> C = A.Date + B.TimeOfDay;
>>>
>>> Except that isn't it.
>>
>> I ended up writing a utility method which did something like this -
>> it's not hard to write once and then use repeatedly. Basically use the
>> form of the DateTime constructor which takes everything you want, and
>> take some parts from A and some parts from B.
>>
>> --
>> Jon Skeet - <(E-Mail Removed)>
>> http://www.pobox.com/~skeet
>> If replying to the group, please do not mail me too
>
>

Ahh, I get you...

DateTime C = new DateTime(A.Year, A.Month, A.Day, B.Hour, B.Minute,
B.Second);

Thanks, that works.

Patrick B wrote:
> How can I assign to C just the date part of A and just the time part of B?
Use the DateTime constructor with Year, Month and Day from DateTime a
and Hour, Minute and Second from DateTime b.

DateTime a=new DateTime(2005,01,04);
DateTime b=DateTime.Now;
DateTime c=new DateTime(a.Year,a.Month,a.Day,b.Hour,b.Minute,b.Second);

Anders Norås
http://dotnetjunkies.com/weblog/anoras/

Patrick B <(E-Mail Removed)> wrote:
> Ahh, I get you...
>
> DateTime C = new DateTime(A.Year, A.Month, A.Day, B.Hour, B.Minute,
> B.Second);
>
> Thanks, that works.

Goodo - but actually, looking at your original post, I don't see why
that shouldn't work. For instance:

using System;

class Test
{
static void Main()
{
DateTime now = DateTime.Now;
DateTime yesterday = DateTime.Today.AddDays(-1);
DateTime thisTimeYesterday = yesterday.Date+now.TimeOfDay;

Console.WriteLine(thisTimeYesterday);
}
}

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

Try This

DateTime A = DateTime.Now;

DateTime B = DateTime.Now.Add(-1);

DateTime C = A.Date.AddTicks(B.TimeOfDay.Ticks);



Ciaran

"Patrick B" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Say I have three DateTime variables:
>
> DateTime A;
> DateTime B;
> DateTime C;
>
> How can I assign to C just the date part of A and just the time part of B?
>
> Something like this...
>
> C = A.Date + B.TimeOfDay;
>
> Except that isn't it.