I have some VB Script that I am writing. To make it simple, I am defining a
function as follows:

'The Code
Function AAAAA(TAKT As String, WeekEnds As String, BuildAhead As String,
DueDate As String, Shifts As String, HoursPerDay As String) As Integer

Dim iDailyProduction As Integer
Dim iBuildAheadTime As Integer
Dim iWeekEndDays As Integer
Dim StraightStartDate As Date
Dim t As Integer
Dim iWeekEndDaysInPeriod As Integer
Dim iDay As Integer

Select Case UCase(WeekEnds)
Case "SUN"
iDay = 1
Case "SAT"
iDay = 7
End Select

iDailyProduction = 3600 * (HoursPerDay - 0.5) / TAKT
iBuildAheadTime = (BuildAhead / iDailyProduction)
AAAAA = DateSerial(1989, 5, 15)

End Function

This is not the complete code, I have eliminated some of it for
troubleshooting purposes.

The problem I am running into is: if I any year less than 1990, the function
operates coorectly. For any date 1990 or greater, the function returns the
#VALUE! error in the cell.

Any ideas?

change the type of your function. Change

Function AAAAA(TAKT As String, WeekEnds As String, BuildAhead As String,
DueDate As String, Shifts As String, HoursPerDay As String) As Integer

to

Function AAAAA(TAKT As String, WeekEnds As String, BuildAhead As String,
DueDate As String, Shifts As String, HoursPerDay As String) As Long

or

Function AAAAA(TAKT As String, WeekEnds As String, BuildAhead As String,
DueDate As String, Shifts As String, HoursPerDay As String) As Date

--
Regards,
Tom Ogilvy

"rockerx" wrote:

> I have some VB Script that I am writing. To make it simple, I am defining a
> function as follows:
>
> 'The Code
> Function AAAAA(TAKT As String, WeekEnds As String, BuildAhead As String,
> DueDate As String, Shifts As String, HoursPerDay As String) As Integer
>
> Dim iDailyProduction As Integer
> Dim iBuildAheadTime As Integer
> Dim iWeekEndDays As Integer
> Dim StraightStartDate As Date
> Dim t As Integer
> Dim iWeekEndDaysInPeriod As Integer
> Dim iDay As Integer
>
> Select Case UCase(WeekEnds)
> Case "SUN"
> iDay = 1
> Case "SAT"
> iDay = 7
> End Select
>
> iDailyProduction = 3600 * (HoursPerDay - 0.5) / TAKT
> iBuildAheadTime = (BuildAhead / iDailyProduction)
> AAAAA = DateSerial(1989, 5, 15)
>
> End Function
>
> This is not the complete code, I have eliminated some of it for
> troubleshooting purposes.
>
> The problem I am running into is: if I any year less than 1990, the function
> operates coorectly. For any date 1990 or greater, the function returns the
> #VALUE! error in the cell.
>
> Any ideas?