You have your answer (several times now), but I just wanted to mention that
when you use a # or 0 symbol in the integer part of a string pattern, that
does *not* restrict the number of digits in the integer part of the number
being processed, it only differentiates whether leading zeroes will be
printed or not. This is different from the decimal part of a floating point
number where the number of # or 0 symbols in the string pattern does
truncate (actually, round) the number of decimal places printed out. So,
whether you used "#", "##", "###", etc. in the integer part of the pattern
string, you would always have gotten 2008 printed out. As the other
responses showed, using the date part meta-characters in the pattern string
allow you to restrict the part of the date printed out.
Rick
"XP" <(E-Mail Removed)> wrote in message
news:FF59EDE9-E5A3-4745-8474-(E-Mail Removed)...
> I'm trying to perfect a formula that produces a two digit year from
> another
> cell that contains a full date, for example:
>
> Y12 contains the following formatted as a date: 07-10-2008
>
> In Y13 my formula is: =TEXT(YEAR(Y12),"##")
>
> No matter what I try I get: 2008 as a result rather than the intended: 08
>
> I'm sure it is obvious, but can someone please assist. Thanks much in
> advance!
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