On Wed, 15 Jul 2009 06:18:14 -0700 (PDT), Paul Black
<(E-Mail Removed)> wrote:
>Hi everyone,
>
>I have a table of lottery numbers where 6 balls are drawn each draw.
>The table is from D3:i whatever and obviously grows constantly.
>The draw number is in column B with the last draw at the bottom.
>What I would like is to list the numbers from 1 to 49 starting in S3
>and going down and next to each number have the number of draws since
>that particular number has been drawn please. So basically, start at
>the bottom right cell of the table and work left and then up to find
>out how many draws it has been since each of the numbers from 1 to 49
>have been drawn.
>
>Thanks in advance.
>Paul
If you have the number 1,2,3, ..., 49 in cells S3, S4, S5, ... S51 you
may try the following formula in cell T3:
=IF(OR(D$3:I$1000=S3),MAX(ROW(D$3

$1000)*(D$3

$1000<>""))-MAX(ROW(D$3:I$1000)*(MMULT(--(D$3:I$1000=S3),{1;1;1;1;1;1})>0)),"newer
drawn")
Note: This is an array formula that has to be confirmed by
CTRL+SHIFT+ENTER rather than just ENTER.
Change the 1000 to suit the size of your data in columns D to I.
Copy the formula down until cell T51.
The numbers in column T now show the number of draws since the
corresponding numbers in column S were drawn.
0 means that the number was in the last draw.
If a number has never been drawn, the text "never drawn" is displayed
in column T.
Hope this helps / Lars-Åke