I could almost do this with a simple find and replace, if I could figure out
how to replace the tab with the required number of spaces (varies from line
to line, depending on length of content before tab).
After converting the table to text, the line from the multi-line cells end
with a manual line break, while each (formerly) cell rowends with a paragraph
mark.
So:
replace [character followed by tab] with X spaces, where x equals the
difference between the location of the tab character and the next tab stop.
replace [line break followed by tab] with a number of spaces equal to the
location of the tab (expressed in character columns)
"Graham Mayor" wrote:
> What you are experiencing is inevitable and nothing to do with the plain
> text nor the tabs. It concerns the fact that if you have multi-line cell
> content, then that content will no longer be multi-line if you convert the
> table to text (or save the document containing the table) as plain text. The
> cell content opens out and displaces the remaining text, which would remain
> tabbed. Frankly I don't see how a macro would be able to sort out such a
> random mess.
>
> --
> <>>< ><<> ><<> <>>< ><<> <>>< <>><<>
> Graham Mayor - Word MVP
>
> My web site www.gmayor.com
> Word MVP web site http://word.mvps.org
> <>>< ><<> ><<> <>>< ><<> <>>< <>><<>
>
> Dion Starfire wrote:
> > Is there a way to convert a tab into however many spaces are needed
> > to reach the next tab stop?
> >
> > I'm trying to convert an html table to a plain text file. Some of the
> > cells contain multiple lines. Currently, I copy into word, convert
> > the table to tab-delimited text, then save as plain text. However,
> > this destroys the column alignment, and messes up the multi-line
> > 'cells'.
> >
> > If there's not a built in function for this, how could I write a
> > macro to do this? (I'm at the 'dabbler' proficiency level, but am
> > very good at using the built-in help system).
>
>
>
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