Is it possible, in a clean way, to convert int values too bool
int i=10;

bool b=(bool)i;


instead of doing b=(i>0);

On Oct 7, 12:27*pm, puzzlecracker <ironsel2...@gmail.com> wrote:
> Is it possible, in a clean way, to convert int values too bool
> int i=10;
>
> bool b=(bool)i;
>
> instead of doing b=(i>0);

I'd argue the statement should be:
bool b = (i != 0)

but this will work too:
bool b = Convert.ToBoolean(i);

> bool b = Convert.ToBoolean(i);

Thanks, that's what I was looking for!

puzzlecracker wrote:
>> bool b = Convert.ToBoolean(i);
>
> Thanks, that's what I was looking for!

And guess how it's implemented?

public static bool ToBoolean(int value) {
return (value != 0);
}



--
Göran Andersson
_____
http://www.guffa.com

On Oct 7, 5:39 pm, Göran Andersson <gu...@guffa.com> wrote:
> puzzlecracker wrote:
> >> bool b = Convert.ToBoolean(i);
>
> > Thanks, that's what I was looking for!
>
> And guess how it's implemented?
>
> public static bool ToBoolean(int value) {
> return (value != 0);
>
> }
>
>
>
> --
Göran Andersson
> _____http://www.guffa.com

Sweet, what about the reverse?

puzzlecracker wrote:
> On Oct 7, 5:39 pm, Göran Andersson <gu...@guffa.com> wrote:
>> puzzlecracker wrote:
>>>> bool b = Convert.ToBoolean(i);
>>> Thanks, that's what I was looking for!
>> And guess how it's implemented?
>>
>> public static bool ToBoolean(int value) {
>> return (value != 0);
>>
>> }
>
> Sweet, what about the reverse?

You mean:

public static int ToInt32(bool value)
{
if (!value)
{
return 0;
}
return 1;
}

?

I don't know why it is not using the ?: operator.

Arne

> You mean:
>
> public static int ToInt32(bool value)
> {
> if (!value)
> {
> return 0;
> }
> return 1;
> }
>
> ?
>
> I don't know why it is not using the ?: operator.

Did you look at the source code or use a decompiler? The MSIL doesn't
provide any distinction that a decompiler could use between an if/else vs
tertiary operator.

>
> Arne

On Oct 9, 11:06*am, "Ben Voigt [C++ MVP]" <r...@nospam.nospam> wrote:
> > You mean:
>
> > public static int ToInt32(bool value)
> > {
> > * * if (!value)
> > * * {
> > * * * * return 0;
> > * * }
> > * * return 1;
> > }
>
> > ?
>
> > I don't know why it is not using the ?: operator.
>
> Did you look at the source code or use a decompiler? *The MSIL doesn't
> provide any distinction that a decompiler could use between an if/else vs
> tertiary operator.
>
>
>
>
>
> > Arne- Hide quoted text -
>
> - Show quoted text -

right.

it basically converts to one and the same

-Cnu

Ben Voigt [C++ MVP] wrote:
>> You mean:
>>
>> public static int ToInt32(bool value)
>> {
>> if (!value)
>> {
>> return 0;
>> }
>> return 1;
>> }
>>
>> ?
>>
>> I don't know why it is not using the ?: operator.
>
> Did you look at the source code or use a decompiler? The MSIL doesn't
> provide any distinction that a decompiler could use between an if/else vs
> tertiary operator.

Reflector.

So it could actually have been a ?: operator ?

Well - easy to test.

public static class ToBeOrNotToBe
{
public static int Foo(bool v)
{
return v ? 1 : 0;
}
public static int Bar(bool v)
{
if(v)
{
return 1;
}
else
{
return 0;
}
}
}

csc and reflector:

public static class ToBeOrNotToBe
{
// Methods
public static int Bar(bool v)
{
if (v)
{
return 1;
}
return 0;
}

public static int Foo(bool v)
{
return (v ? 1 : 0);
}
}

csc /o+ and reflector:

public static class ToBeOrNotToBe
{
// Methods
public static int Bar(bool v)
{
if (v)
{
return 1;
}
return 0;
}

public static int Foo(bool v)
{
if (!v)
{
return 0;
}
return 1;
}
}

Yes - it looks as if the ?: has been used after all.

Arne