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conversion to c# from excel function help

 
 
D
Guest
Posts: n/a
 
      9th Feb 2005
I am trying to do this in C#

Function Num2Let(L As Long) As String
Dim s0 As String, s1 As String, S2 As String, s3 As String
If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 + 65)
s3 = Chr(((L - 1) Mod 26) + 65)
Num2Let = s0 & s1 & S2 & s3
End Function

it takes a long and converts it to the excel header format of AA, BQ DS etc

so far I have this, I commented out the top and worked my way up from the
bottom. I'm not sure what the c# equivalent of Int in excel (which returns
the 210 part of 210.2342) and I don't know what how this is handled
Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);

Thanks for any help.


public string Num2Let(long L )

{

string s0, s1, S2, s3, final;

/* if(L > 18278)

s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);

if(L > 702)

s1 = Chr((Int((L - 703) / 676) % 26) + 65);

*/

if(L > 26)

S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);

//S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);

long x =(((L - 1) % 26) + 65);

char c = (char)x;

s3 = c.ToString();

//final = s0 + s1 + S2 + s3;

return s3;

}


 
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RCS
Guest
Posts: n/a
 
      9th Feb 2005
Man, you should make up a book of these and sell them at geek stores, you'd
make a fortune!!

If this doesn't get solved tonight, I'll give it a shot tomorrow - looks
fun!!


"D" <(E-Mail Removed)> wrote in message
news:%(E-Mail Removed)...
>I am trying to do this in C#
>
> Function Num2Let(L As Long) As String
> Dim s0 As String, s1 As String, S2 As String, s3 As String
> If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
> If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
> If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 + 65)
> s3 = Chr(((L - 1) Mod 26) + 65)
> Num2Let = s0 & s1 & S2 & s3
> End Function
>
> it takes a long and converts it to the excel header format of AA, BQ DS
> etc
>
> so far I have this, I commented out the top and worked my way up from the
> bottom. I'm not sure what the c# equivalent of Int in excel (which returns
> the 210 part of 210.2342) and I don't know what how this is handled
> Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>
> Thanks for any help.
>
>
> public string Num2Let(long L )
>
> {
>
> string s0, s1, S2, s3, final;
>
> /* if(L > 18278)
>
> s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);
>
> if(L > 702)
>
> s1 = Chr((Int((L - 703) / 676) % 26) + 65);
>
> */
>
> if(L > 26)
>
> S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);
>
> //S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>
> long x =(((L - 1) % 26) + 65);
>
> char c = (char)x;
>
> s3 = c.ToString();
>
> //final = s0 + s1 + S2 + s3;
>
> return s3;
>
> }
>
>



 
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D
Guest
Posts: n/a
 
      9th Feb 2005
I wish I could but I didn't write it. I found it when I was looking for a
function to convert numbers to excel like headers (AAA, AAB, AAC etc).

I'll post the solution if I figure it out.


"RCS" <(E-Mail Removed)> wrote in message
news:VugOd.3721$(E-Mail Removed)...
> Man, you should make up a book of these and sell them at geek stores,
> you'd make a fortune!!
>
> If this doesn't get solved tonight, I'll give it a shot tomorrow - looks
> fun!!
>
>
> "D" <(E-Mail Removed)> wrote in message
> news:%(E-Mail Removed)...
>>I am trying to do this in C#
>>
>> Function Num2Let(L As Long) As String
>> Dim s0 As String, s1 As String, S2 As String, s3 As String
>> If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
>> If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
>> If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 + 65)
>> s3 = Chr(((L - 1) Mod 26) + 65)
>> Num2Let = s0 & s1 & S2 & s3
>> End Function
>>
>> it takes a long and converts it to the excel header format of AA, BQ DS
>> etc
>>
>> so far I have this, I commented out the top and worked my way up from the
>> bottom. I'm not sure what the c# equivalent of Int in excel (which
>> returns the 210 part of 210.2342) and I don't know what how this is
>> handled Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>
>> Thanks for any help.
>>
>>
>> public string Num2Let(long L )
>>
>> {
>>
>> string s0, s1, S2, s3, final;
>>
>> /* if(L > 18278)
>>
>> s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);
>>
>> if(L > 702)
>>
>> s1 = Chr((Int((L - 703) / 676) % 26) + 65);
>>
>> */
>>
>> if(L > 26)
>>
>> S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);
>>
>> //S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>
>> long x =(((L - 1) % 26) + 65);
>>
>> char c = (char)x;
>>
>> s3 = c.ToString();
>>
>> //final = s0 + s1 + S2 + s3;
>>
>> return s3;
>>
>> }
>>
>>

>
>



 
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Dennis Myrén
Guest
Posts: n/a
 
      9th Feb 2005
Try this one.
I needed one myself too. Cool!

Do not know if it works yet.

public static string CellIndexToName ( int index )
{
if (0x0 >= index)
return string.Empty;
StringBuilder sb = new StringBuilder(0x5);
if (0x4766 < index)
{
sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x4767)) /
17576)) % 0x1a) + 0x41));
}
if (0x2BE < index)
{
sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x2bf)) /
676)) % 0x1a) + 0x41));
}
if (0x1A < index)
{
sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x1b)) /
26)) % 0x1a) + 0x41));
}
sb.Append((char) (int) (((index - 0x1) % 0x1A) + 0x41));
return sb.ToString();
}


--
Regards,
Dennis JD Myrén
Oslo Kodebureau
"D" <(E-Mail Removed)> wrote in message
news:%(E-Mail Removed)...
>I wish I could but I didn't write it. I found it when I was looking for a
>function to convert numbers to excel like headers (AAA, AAB, AAC etc).
>
> I'll post the solution if I figure it out.
>
>
> "RCS" <(E-Mail Removed)> wrote in message
> news:VugOd.3721$(E-Mail Removed)...
>> Man, you should make up a book of these and sell them at geek stores,
>> you'd make a fortune!!
>>
>> If this doesn't get solved tonight, I'll give it a shot tomorrow - looks
>> fun!!
>>
>>
>> "D" <(E-Mail Removed)> wrote in message
>> news:%(E-Mail Removed)...
>>>I am trying to do this in C#
>>>
>>> Function Num2Let(L As Long) As String
>>> Dim s0 As String, s1 As String, S2 As String, s3 As String
>>> If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
>>> If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
>>> If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 + 65)
>>> s3 = Chr(((L - 1) Mod 26) + 65)
>>> Num2Let = s0 & s1 & S2 & s3
>>> End Function
>>>
>>> it takes a long and converts it to the excel header format of AA, BQ DS
>>> etc
>>>
>>> so far I have this, I commented out the top and worked my way up from
>>> the bottom. I'm not sure what the c# equivalent of Int in excel (which
>>> returns the 210 part of 210.2342) and I don't know what how this is
>>> handled Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>
>>> Thanks for any help.
>>>
>>>
>>> public string Num2Let(long L )
>>>
>>> {
>>>
>>> string s0, s1, S2, s3, final;
>>>
>>> /* if(L > 18278)
>>>
>>> s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);
>>>
>>> if(L > 702)
>>>
>>> s1 = Chr((Int((L - 703) / 676) % 26) + 65);
>>>
>>> */
>>>
>>> if(L > 26)
>>>
>>> S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);
>>>
>>> //S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>
>>> long x =(((L - 1) % 26) + 65);
>>>
>>> char c = (char)x;
>>>
>>> s3 = c.ToString();
>>>
>>> //final = s0 + s1 + S2 + s3;
>>>
>>> return s3;
>>>
>>> }
>>>
>>>

>>
>>

>
>



 
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D
Guest
Posts: n/a
 
      9th Feb 2005
BRILLIANT!!!!!

Works fine for me so far.

Can you tell me why you used hex (0x0 , 0x4766, etc)?

Thanks alot!!!


"Dennis Myrén" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Try this one.
> I needed one myself too. Cool!
>
> Do not know if it works yet.
>
> public static string CellIndexToName ( int index )
> {
> if (0x0 >= index)
> return string.Empty;
> StringBuilder sb = new StringBuilder(0x5);
> if (0x4766 < index)
> {
> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x4767)) /
> 17576)) % 0x1a) + 0x41));
> }
> if (0x2BE < index)
> {
> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x2bf)) /
> 676)) % 0x1a) + 0x41));
> }
> if (0x1A < index)
> {
> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x1b)) /
> 26)) % 0x1a) + 0x41));
> }
> sb.Append((char) (int) (((index - 0x1) % 0x1A) + 0x41));
> return sb.ToString();
> }
>
>
> --
> Regards,
> Dennis JD Myrén
> Oslo Kodebureau
> "D" <(E-Mail Removed)> wrote in message
> news:%(E-Mail Removed)...
>>I wish I could but I didn't write it. I found it when I was looking for a
>>function to convert numbers to excel like headers (AAA, AAB, AAC etc).
>>
>> I'll post the solution if I figure it out.
>>
>>
>> "RCS" <(E-Mail Removed)> wrote in message
>> news:VugOd.3721$(E-Mail Removed)...
>>> Man, you should make up a book of these and sell them at geek stores,
>>> you'd make a fortune!!
>>>
>>> If this doesn't get solved tonight, I'll give it a shot tomorrow - looks
>>> fun!!
>>>
>>>
>>> "D" <(E-Mail Removed)> wrote in message
>>> news:%(E-Mail Removed)...
>>>>I am trying to do this in C#
>>>>
>>>> Function Num2Let(L As Long) As String
>>>> Dim s0 As String, s1 As String, S2 As String, s3 As String
>>>> If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
>>>> If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
>>>> If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 + 65)
>>>> s3 = Chr(((L - 1) Mod 26) + 65)
>>>> Num2Let = s0 & s1 & S2 & s3
>>>> End Function
>>>>
>>>> it takes a long and converts it to the excel header format of AA, BQ DS
>>>> etc
>>>>
>>>> so far I have this, I commented out the top and worked my way up from
>>>> the bottom. I'm not sure what the c# equivalent of Int in excel (which
>>>> returns the 210 part of 210.2342) and I don't know what how this is
>>>> handled Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>>
>>>> Thanks for any help.
>>>>
>>>>
>>>> public string Num2Let(long L )
>>>>
>>>> {
>>>>
>>>> string s0, s1, S2, s3, final;
>>>>
>>>> /* if(L > 18278)
>>>>
>>>> s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);
>>>>
>>>> if(L > 702)
>>>>
>>>> s1 = Chr((Int((L - 703) / 676) % 26) + 65);
>>>>
>>>> */
>>>>
>>>> if(L > 26)
>>>>
>>>> S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);
>>>>
>>>> //S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>>
>>>> long x =(((L - 1) % 26) + 65);
>>>>
>>>> char c = (char)x;
>>>>
>>>> s3 = c.ToString();
>>>>
>>>> //final = s0 + s1 + S2 + s3;
>>>>
>>>> return s3;
>>>>
>>>> }
>>>>
>>>>
>>>
>>>

>>
>>

>
>



 
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Dennis Myrén
Guest
Posts: n/a
 
      9th Feb 2005
So it works? Cool!
Have'nt really got the time to test it properly, just a few times with small
numbers.

There is no particular reason why i use hex instead of decimals, it is just
a matter
of preference, and maybe decimals would be clearer when posting code here.


--
Regards,
Dennis JD Myrén
Oslo Kodebureau
"D" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> BRILLIANT!!!!!
>
> Works fine for me so far.
>
> Can you tell me why you used hex (0x0 , 0x4766, etc)?
>
> Thanks alot!!!
>
>
> "Dennis Myrén" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
>> Try this one.
>> I needed one myself too. Cool!
>>
>> Do not know if it works yet.
>>
>> public static string CellIndexToName ( int index )
>> {
>> if (0x0 >= index)
>> return string.Empty;
>> StringBuilder sb = new StringBuilder(0x5);
>> if (0x4766 < index)
>> {
>> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x4767))
>> / 17576)) % 0x1a) + 0x41));
>> }
>> if (0x2BE < index)
>> {
>> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x2bf)) /
>> 676)) % 0x1a) + 0x41));
>> }
>> if (0x1A < index)
>> {
>> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x1b)) /
>> 26)) % 0x1a) + 0x41));
>> }
>> sb.Append((char) (int) (((index - 0x1) % 0x1A) + 0x41));
>> return sb.ToString();
>> }
>>
>>
>> --
>> Regards,
>> Dennis JD Myrén
>> Oslo Kodebureau
>> "D" <(E-Mail Removed)> wrote in message
>> news:%(E-Mail Removed)...
>>>I wish I could but I didn't write it. I found it when I was looking for a
>>>function to convert numbers to excel like headers (AAA, AAB, AAC etc).
>>>
>>> I'll post the solution if I figure it out.
>>>
>>>
>>> "RCS" <(E-Mail Removed)> wrote in message
>>> news:VugOd.3721$(E-Mail Removed)...
>>>> Man, you should make up a book of these and sell them at geek stores,
>>>> you'd make a fortune!!
>>>>
>>>> If this doesn't get solved tonight, I'll give it a shot tomorrow -
>>>> looks fun!!
>>>>
>>>>
>>>> "D" <(E-Mail Removed)> wrote in message
>>>> news:%(E-Mail Removed)...
>>>>>I am trying to do this in C#
>>>>>
>>>>> Function Num2Let(L As Long) As String
>>>>> Dim s0 As String, s1 As String, S2 As String, s3 As String
>>>>> If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
>>>>> If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
>>>>> If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 + 65)
>>>>> s3 = Chr(((L - 1) Mod 26) + 65)
>>>>> Num2Let = s0 & s1 & S2 & s3
>>>>> End Function
>>>>>
>>>>> it takes a long and converts it to the excel header format of AA, BQ
>>>>> DS etc
>>>>>
>>>>> so far I have this, I commented out the top and worked my way up from
>>>>> the bottom. I'm not sure what the c# equivalent of Int in excel (which
>>>>> returns the 210 part of 210.2342) and I don't know what how this is
>>>>> handled Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>>>
>>>>> Thanks for any help.
>>>>>
>>>>>
>>>>> public string Num2Let(long L )
>>>>>
>>>>> {
>>>>>
>>>>> string s0, s1, S2, s3, final;
>>>>>
>>>>> /* if(L > 18278)
>>>>>
>>>>> s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);
>>>>>
>>>>> if(L > 702)
>>>>>
>>>>> s1 = Chr((Int((L - 703) / 676) % 26) + 65);
>>>>>
>>>>> */
>>>>>
>>>>> if(L > 26)
>>>>>
>>>>> S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);
>>>>>
>>>>> //S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>>>
>>>>> long x =(((L - 1) % 26) + 65);
>>>>>
>>>>> char c = (char)x;
>>>>>
>>>>> s3 = c.ToString();
>>>>>
>>>>> //final = s0 + s1 + S2 + s3;
>>>>>
>>>>> return s3;
>>>>>
>>>>> }
>>>>>
>>>>>
>>>>
>>>>
>>>
>>>

>>
>>

>
>



 
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D
Guest
Posts: n/a
 
      9th Feb 2005
I haven't pushed it to the higher limits but so far it works good.

> There is no particular reason why i use hex instead of decimals, it is
> just


It looks cooler!

I worked with a guy who always wrote his if's in a similiar fashion although
not hex but put the number first like
this
if ( 1 < x )
versus
if ( x > 1 )


he said the reason was that it was a faster action in the cpu. I don't know
about that but it "sounded good to management."

Thanks again.



"Dennis Myrén" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> So it works? Cool!
> Have'nt really got the time to test it properly, just a few times with
> small numbers.
>
> There is no particular reason why i use hex instead of decimals, it is
> just a matter
> of preference, and maybe decimals would be clearer when posting code here.
>
>
> --
> Regards,
> Dennis JD Myrén
> Oslo Kodebureau
> "D" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
>> BRILLIANT!!!!!
>>
>> Works fine for me so far.
>>
>> Can you tell me why you used hex (0x0 , 0x4766, etc)?
>>
>> Thanks alot!!!
>>
>>
>> "Dennis Myrén" <(E-Mail Removed)> wrote in message
>> news:(E-Mail Removed)...
>>> Try this one.
>>> I needed one myself too. Cool!
>>>
>>> Do not know if it works yet.
>>>
>>> public static string CellIndexToName ( int index )
>>> {
>>> if (0x0 >= index)
>>> return string.Empty;
>>> StringBuilder sb = new StringBuilder(0x5);
>>> if (0x4766 < index)
>>> {
>>> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x4767))
>>> / 17576)) % 0x1a) + 0x41));
>>> }
>>> if (0x2BE < index)
>>> {
>>> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x2bf))
>>> / 676)) % 0x1a) + 0x41));
>>> }
>>> if (0x1A < index)
>>> {
>>> sb.Append((char) ((int) ((int) ((double) (((double) (index - 0x1b)) /
>>> 26)) % 0x1a) + 0x41));
>>> }
>>> sb.Append((char) (int) (((index - 0x1) % 0x1A) + 0x41));
>>> return sb.ToString();
>>> }
>>>
>>>
>>> --
>>> Regards,
>>> Dennis JD Myrén
>>> Oslo Kodebureau
>>> "D" <(E-Mail Removed)> wrote in message
>>> news:%(E-Mail Removed)...
>>>>I wish I could but I didn't write it. I found it when I was looking for
>>>>a function to convert numbers to excel like headers (AAA, AAB, AAC etc).
>>>>
>>>> I'll post the solution if I figure it out.
>>>>
>>>>
>>>> "RCS" <(E-Mail Removed)> wrote in message
>>>> news:VugOd.3721$(E-Mail Removed)...
>>>>> Man, you should make up a book of these and sell them at geek stores,
>>>>> you'd make a fortune!!
>>>>>
>>>>> If this doesn't get solved tonight, I'll give it a shot tomorrow -
>>>>> looks fun!!
>>>>>
>>>>>
>>>>> "D" <(E-Mail Removed)> wrote in message
>>>>> news:%(E-Mail Removed)...
>>>>>>I am trying to do this in C#
>>>>>>
>>>>>> Function Num2Let(L As Long) As String
>>>>>> Dim s0 As String, s1 As String, S2 As String, s3 As String
>>>>>> If L > 18278 Then s0 = Chr((Int((L - 18279) / 17576) Mod 26) + 65)
>>>>>> If L > 702 Then s1 = Chr((Int((L - 703) / 676) Mod 26) + 65)
>>>>>> If L > 26 Then S2 = Chr(Num2Let & (Int((L - 27) / 26)) Mod 26 +
>>>>>> 65)
>>>>>> s3 = Chr(((L - 1) Mod 26) + 65)
>>>>>> Num2Let = s0 & s1 & S2 & s3
>>>>>> End Function
>>>>>>
>>>>>> it takes a long and converts it to the excel header format of AA, BQ
>>>>>> DS etc
>>>>>>
>>>>>> so far I have this, I commented out the top and worked my way up from
>>>>>> the bottom. I'm not sure what the c# equivalent of Int in excel
>>>>>> (which returns the 210 part of 210.2342) and I don't know what how
>>>>>> this is handled Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>>>>
>>>>>> Thanks for any help.
>>>>>>
>>>>>>
>>>>>> public string Num2Let(long L )
>>>>>>
>>>>>> {
>>>>>>
>>>>>> string s0, s1, S2, s3, final;
>>>>>>
>>>>>> /* if(L > 18278)
>>>>>>
>>>>>> s0 = Chr((Int((L - 18279) / 17576) % 26) + 65);
>>>>>>
>>>>>> if(L > 702)
>>>>>>
>>>>>> s1 = Chr((Int((L - 703) / 676) % 26) + 65);
>>>>>>
>>>>>> */
>>>>>>
>>>>>> if(L > 26)
>>>>>>
>>>>>> S2 = Chr(Num2Let(((L - 27) / 26)) % 26 + 65);
>>>>>>
>>>>>> //S2 = Chr(Num2Let & ( Int((L - 27) / 26) ) % 26 + 65);
>>>>>>
>>>>>> long x =(((L - 1) % 26) + 65);
>>>>>>
>>>>>> char c = (char)x;
>>>>>>
>>>>>> s3 = c.ToString();
>>>>>>
>>>>>> //final = s0 + s1 + S2 + s3;
>>>>>>
>>>>>> return s3;
>>>>>>
>>>>>> }
>>>>>>
>>>>>>
>>>>>
>>>>>
>>>>
>>>>
>>>
>>>

>>
>>

>
>



 
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