I am recieving a #N/A in the field. This is what it looks like now that I
modified it to fit what I am doing. Can you see what may be wrong? $E$8 is
the lookup value and the table is in $P$2:$Z$41.
=INDEX($Q$3:$Z$41,MATCH(ROUND($E$8,1),$P$3:$P$41,0),MATCH($E$8-ROUND($E$8,1),$Q$2:$Z$2,0))
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Thank you!
"Glenn" wrote:
> Doug wrote:
> > I have a lookup table that I need to reference. based on a 3 digit # such as
> > "2.22", I need to be able to find the cross section on the lookup table.
> > Based on numbers across the top and down the left side;
> > If I have the number 2.22, it will return for me .15 from the table
> >
> > lookup table (made up values)
> > .00 .01 .02 .03 .04 ... .09
> > 2.0 .31 .32 .33 .34 .35 ... .50
> > 2.1 .21 .35 .51 .51 .25 ... .85
> > 2.2 .53 .52 .15 .52 .51 ... .81
> > 2.3 .89 .58 .23 .45 .15 ... .15
>
>
> http://www.contextures.com/xlFunctio...ml#IndexMatch2
>
> Assuming your table above is in A1:K5, and 2.22 is in A10, try this:
>
> =INDEX($B$2:$K$5,MATCH(ROUND(A10,1),$A$2:$A$5,0),
> MATCH(A10-ROUND(A10,1),$B$1:$K$1,0))
> .
>