Thank you both, I choose to use the formula solutuion,
Jan
Rick Rothstein wrote:
> This array-entered** formula should do what you want...
>
> =10-MAX(IF(A1:J1<>A2:J2,COLUMN(A1:J1),0))
>
> **Commit formula using Ctrl+Shift+Enter, not just Enter by itself.
>
> Note... the value of 10 represents the column number of the last
> column in the range (Column J is the 10th column).
>
>
> "Jan Kronsell" <kronsell(nomorespam)@adslhome.dk> wrote in message
> news:OBJoF%(E-Mail Removed)...
>> I column A to J, row 1 and two I have numbers between 1 and 9.
>>
>> It might look like this
>>
>> 1 1 1 2 3 1 1 1 1 1
>> 1 1 1 1 8 2 1 1 1 1
>>
>> What I need is a function that compares the two rows, like this:
>>
>> If J1 and J2 contains the same number, it must be counted.
>> Next it should test i I1 and I2 contaisn the same number. I n that
>> case it should be addes to the counter.
>> The code should go on like this until it meets to numbers, thatr are
>> not the same. Then it should stop counting and return the resulat of
>> the counter.
>>
>> In other words it shold compare the numbers in row 1 and 2, going
>> backwatrds from column J to column A. The first time two numbers are
>> not the same, it should stop, and return the number counted.
>>
>> Maby the function could be entered like =COUNTALIKE(A1:J2) and the
>> above caee the result should be 4 as there are four numbers, that
>> are the same, before the that are not.
>>
>> Jan
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