> In computer algebra software such as
> Matlab,S-plus or R, I am used to be able to specify a particular range of
> indexes , i.e matrix(1:90,120) where 1:90 is row 1 to 90, and 120 the
> 120th
Hi. Not sure if this could help or not.
You may be able to take an entire column, but it is hard to take parts of a
single array.
Here, V is made of "All" Rows of the second Column.
Then, Redim is used to shrink the array down to the first two values.
It won't work if the index doesn't start at 1.
Sub Demo()
Dim Fx As WorksheetFunction
Dim M(), V
Const All As Long = 0
Set Fx = WorksheetFunction
M = [{1,2,3;4,5,6;7,8,9}]
V = Fx.Transpose(Fx.Index(M, All, 2))
ReDim Preserve V(1)
End Sub
It's kind of similar to math programs...
M = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
M[[All,2]]
{2, 5, 8}
Does making your Matrix a Public variable help?
--
HTH :>)
Dana DeLouis
Windows XP & Office 2003
"STIG" <(E-Mail Removed)> wrote in message
news:BDB50CE0-36AE-4E8D-B7D8-(E-Mail Removed)...
> Hi!
> In a class module I have declared a matrix ( name(120,120) as double), i
> have a sub procedure that does som calculations, so that I have the
> information I want to use for calculations stored in that matrix. In a
> generall module procedures I want to have access to a column of this
> matrix,
> but I haven't got a clue as how to get hold of it. Preferably I would
> like
> to assign a double variable of length 120 the contents of a column of my
> choice belonging to an instance of that class.
> Since the variable is of type (120,120)double I can not access it in the
> usual way by the syntax object.matrix(i,j). Also, is there a way of
> selecting
> multiple indexes in a vector? In computer algebra software such as
> Matlab,S-plus or R, I am used to be able to specify a particular range of
> indexes , i.e matrix(1:90,120) where 1:90 is row 1 to 90, and 120 the
> 120th
> column. Is there any way of doing such an opperation using VBA/Excel.
> Any suggestion on how to solve my problem, or links to sites where I can
> read up on these matters will be greatly apprectiated.
>
> Stig