Hi all
I wonder if you can help me with a query I have. I want to find the number
of cells in a row (for example row A) which contain the word London. The
problem is that in some cell the word is contained as part of other text so
if for example the cell A1 contains the text “50 Kingsway, London, WC1� the
function =if(A1="London",1,0) returns the value of 0 failing to capture the
word “London� which is contained in the cell. Can you propose a solution? Can
I do that with VB?
The problem is that I have a spreadsheet with 80,000 cells in row A so I
need to have 80,000 cells in row B that will check the values of row A (eg B2
will perform the check in A2). This would make my desktop really slow to
perform the checks. Can you help with that issue as well? Thank you in
advance.

Try this:-

=SUMPRODUCT(--(NOT(ISERROR(SEARCH("London",A1:A1000)))))

Mike

"T.Mad" wrote:

> Hi all
> I wonder if you can help me with a query I have. I want to find the number
> of cells in a row (for example row A) which contain the word London. The
> problem is that in some cell the word is contained as part of other text so
> if for example the cell A1 contains the text “50 Kingsway, London, WC1� the
> function =if(A1="London",1,0) returns the value of 0 failing to capture the
> word “London� which is contained in the cell. Can you propose a solution? Can
> I do that with VB?
> The problem is that I have a spreadsheet with 80,000 cells in row A so I
> need to have 80,000 cells in row B that will check the values of row A (eg B2
> will perform the check in A2). This would make my desktop really slow to
> perform the checks. Can you help with that issue as well? Thank you in
> advance.

Thanks Mike it worked.


"Mike H" wrote:

> Try this:-
>
> =SUMPRODUCT(--(NOT(ISERROR(SEARCH("London",A1:A1000)))))
>
> Mike
>
> "T.Mad" wrote:
>
> > Hi all
> > I wonder if you can help me with a query I have. I want to find the number
> > of cells in a row (for example row A) which contain the word London. The
> > problem is that in some cell the word is contained as part of other text so
> > if for example the cell A1 contains the text “50 Kingsway, London, WC1� the
> > function =if(A1="London",1,0) returns the value of 0 failing to capture the
> > word “London� which is contained in the cell. Can you propose a solution? Can
> > I do that with VB?
> > The problem is that I have a spreadsheet with 80,000 cells in row A so I
> > need to have 80,000 cells in row B that will check the values of row A (eg B2
> > will perform the check in A2). This would make my desktop really slow to
> > perform the checks. Can you help with that issue as well? Thank you in
> > advance.

On Tue, 3 Jul 2007 02:08:01 -0700, T.Mad <(E-Mail Removed)>
wrote:

>Hi all
>I wonder if you can help me with a query I have. I want to find the number
>of cells in a row (for example row A) which contain the word London. The
>problem is that in some cell the word is contained as part of other text so
>if for example the cell A1 contains the text “50 Kingsway, London, WC1” the
>function =if(A1="London",1,0) returns the value of 0 failing to capture the
>word “London” which is contained in the cell. Can you propose a solution? Can
>I do that with VB?
>The problem is that I have a spreadsheet with 80,000 cells in row A so I
>need to have 80,000 cells in row B that will check the values of row A (eg B2
>will perform the check in A2). This would make my desktop really slow to
>perform the checks. Can you help with that issue as well? Thank you in
>advance.



One way is to use wild cards in the COUNTIF function:

=COUNTIF(rng_to_check,"*London*")


--ron

And the last question:
Adopting Ron’s proposal I want check three cells in the same row to make
sure that I didn’t count the word more than once. Thus, I will use the
function =IF(COUNTIF(I1:L1,"*London*")>1,1,COUNTIF(I1:L1,"*London*")). And as
a last step I want to add all the results without using 80,000 functions thus
something like:
=SUM(IF(COUNTIF(I1:L1,"*London*")>1,1,COUNTIF(I1:L1,"*London*")):IF(COUNTIF(I80000:L80000,"*London*")>1,1,COUNTIF(I80000:L80000,"*London*"))).
How can I do that?


"Ron Rosenfeld" wrote:

> On Tue, 3 Jul 2007 02:08:01 -0700, T.Mad <(E-Mail Removed)>
> wrote:
>
> >Hi all
> >I wonder if you can help me with a query I have. I want to find the number
> >of cells in a row (for example row A) which contain the word London. The
> >problem is that in some cell the word is contained as part of other text so
> >if for example the cell A1 contains the text “50 Kingsway, London, WC1� the
> >function =if(A1="London",1,0) returns the value of 0 failing to capture the
> >word “London� which is contained in the cell. Can you propose a solution? Can
> >I do that with VB?
> >The problem is that I have a spreadsheet with 80,000 cells in row A so I
> >need to have 80,000 cells in row B that will check the values of row A (eg B2
> >will perform the check in A2). This would make my desktop really slow to
> >perform the checks. Can you help with that issue as well? Thank you in
> >advance.
>
>
>
> One way is to use wild cards in the COUNTIF function:
>
> =COUNTIF(rng_to_check,"*London*")
>
>
> --ron
>