I have a bat file in which I need to know the last node of a directory
string. I know that I am not properly describing it so let me give an
example...

Assuming that I am executing a bat file from the directory path
C:\TestPrograms\Version6\Release2

I would like to be able to obtain the last node ("Release2"). I've tried
everything but can't seem to get this to work.

I tried something like the following
SET FullPath=%CD%
cd..
SET PartPath=%CD%

At this point
FullPath=C:\TestPrograms\Version6\Release2
and
PartPath=C:\TestPrograms\Version6

I tried executing the following to essentially change
"C:\TestPrograms\Version6" to empty string but it didn't work as I had hoped
SET LastNode = %FullPath:%PartPath=%

Any help would be greatly appreciated.

TJT wrote:
> I have a bat file in which I need to know the last node of a directory
> string. I know that I am not properly describing it so let me give an
> example...
>
> Assuming that I am executing a bat file from the directory path
> C:\TestPrograms\Version6\Release2
>
> I would like to be able to obtain the last node ("Release2"). I've tried
> everything but can't seem to get this to work.
>
> I tried something like the following
> SET FullPath=%CD%
> cd..
> SET PartPath=%CD%
>
> At this point
> FullPath=C:\TestPrograms\Version6\Release2
> and
> PartPath=C:\TestPrograms\Version6
>
> I tried executing the following to essentially change
> "C:\TestPrograms\Version6" to empty string but it didn't work as I had hoped
> SET LastNode = %FullPath:%PartPath=%
>
> Any help would be greatly appreciated.
>
>
>

If you have Win2000 or WinXP, you can use delayed expansion:

set LastNode=!FullPath:%PartPath%=!

If you have NT4.0:

call set LastNode=%%FullPath:%PartPath%=%%

--
Phil Robyn
Univ. of California, Berkeley

u n z i p m y a d d r e s s t o s e n d e - m a i l

Phil - Thanks for the reply.

I tried executing the following test batch....
@echo off
SET FullPath=C:\TestPrograms\Version6\Release2
SET PartPath=C:\TestPrograms\Version6

echo FullPath=%FullPath%
echo PartPath=%PartPath%

set LastNode=!FullPath:%PartPath%=!
echo LastNode=%LastNode%


I was hoping to get LastNode=Version6 but I am not getting it. Here's the
output from the batch...
FullPath=C:\TestPrograms\Version6\Release2
PartPath=C:\TestPrograms\Version6
LastNode=!FullPath:C:\TestPrograms\Version6=!

Thanks,
Tom
"Phil Robyn" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> TJT wrote:
> > I have a bat file in which I need to know the last node of a directory
> > string. I know that I am not properly describing it so let me give an
> > example...
> >
> > Assuming that I am executing a bat file from the directory path
> > C:\TestPrograms\Version6\Release2
> >
> > I would like to be able to obtain the last node ("Release2"). I've
tried
> > everything but can't seem to get this to work.
> >
> > I tried something like the following
> > SET FullPath=%CD%
> > cd..
> > SET PartPath=%CD%
> >
> > At this point
> > FullPath=C:\TestPrograms\Version6\Release2
> > and
> > PartPath=C:\TestPrograms\Version6
> >
> > I tried executing the following to essentially change
> > "C:\TestPrograms\Version6" to empty string but it didn't work as I had
hoped
> > SET LastNode = %FullPath:%PartPath=%
> >
> > Any help would be greatly appreciated.
> >
> >
> >
>
> If you have Win2000 or WinXP, you can use delayed expansion:
>
> set LastNode=!FullPath:%PartPath%=!
>
> If you have NT4.0:
>
> call set LastNode=%%FullPath:%PartPath%=%%
>
> --
> Phil Robyn
> Univ. of California, Berkeley
>
> u n z i p m y a d d r e s s t o s e n d e - m a i l

TJT wrote:

> Phil - Thanks for the reply.
>
> I tried executing the following test batch....
> @echo off
> SET FullPath=C:\TestPrograms\Version6\Release2
> SET PartPath=C:\TestPrograms\Version6
>
> echo FullPath=%FullPath%
> echo PartPath=%PartPath%
>
> set LastNode=!FullPath:%PartPath%=!
> echo LastNode=%LastNode%
>
>
> I was hoping to get LastNode=Version6 but I am not getting it. Here's the
> output from the batch...

The last node is 'Release2'. How could you hope to get 'LastNode=Version6'?

> FullPath=C:\TestPrograms\Version6\Release2
> PartPath=C:\TestPrograms\Version6
> LastNode=!FullPath:C:\TestPrograms\Version6=!
>
> Thanks,
> Tom

For Win2000 or WinXP:

C:\cmd>demo\zzzz
FullPath=C:\TestPrograms\Version6\Release2
PartPath=C:\TestPrograms\Version6
LastNode=\Release2

C:\cmd>rlist demo\zzzz.cmd
=====begin C:\cmd\demo\zzzz.cmd ====================
01. @echo off
02. setlocal ENABLEDELAYEDEXPANSION
03. SET FullPath=C:\TestPrograms\Version6\Release2
04. SET PartPath=C:\TestPrograms\Version6
05.
06. echo FullPath=%FullPath%
07. echo PartPath=%PartPath%
08.
09. set LastNode=!FullPath:%PartPath%=!
10. echo LastNode=%LastNode%
=====end C:\cmd\demo\zzzz.cmd ====================

For WinNT4.0:

C:\cmd>demo\zzzz40
FullPath=C:\TestPrograms\Version6\Release2
PartPath=C:\TestPrograms\Version6
LastNode=\Release2

C:\cmd>rlist demo\zzzz40.cmd
=====begin C:\cmd\demo\zzzz40.cmd ====================
01. @echo off
02. setlocal
03. SET FullPath=C:\TestPrograms\Version6\Release2
04. SET PartPath=C:\TestPrograms\Version6
05.
06. echo FullPath=%FullPath%
07. echo PartPath=%PartPath%
08.
09. call set LastNode=%%FullPath:%PartPath%=%%
10. echo LastNode=%LastNode%
=====end C:\cmd\demo\zzzz40.cmd ====================

> "Phil Robyn" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
>
>>TJT wrote:
>>
>>>I have a bat file in which I need to know the last node of a directory
>>>string. I know that I am not properly describing it so let me give an
>>>example...
>>>
>>>Assuming that I am executing a bat file from the directory path
>>> C:\TestPrograms\Version6\Release2
>>>
>>>I would like to be able to obtain the last node ("Release2"). I've
>
> tried
>
>>>everything but can't seem to get this to work.
>>>
>>>I tried something like the following
>>>SET FullPath=%CD%
>>>cd..
>>>SET PartPath=%CD%
>>>
>>>At this point
>>> FullPath=C:\TestPrograms\Version6\Release2
>>>and
>>> PartPath=C:\TestPrograms\Version6
>>>
>>>I tried executing the following to essentially change
>>>"C:\TestPrograms\Version6" to empty string but it didn't work as I had
>
> hoped
>
>>>SET LastNode = %FullPath:%PartPath=%
>>>
>>>Any help would be greatly appreciated.
>>>
>>>
>>>
>>
>>If you have Win2000 or WinXP, you can use delayed expansion:
>>
>> set LastNode=!FullPath:%PartPath%=!
>>
>>If you have NT4.0:
>>
>> call set LastNode=%%FullPath:%PartPath%=%%
>>
>>--
>>Phil Robyn
>>Univ. of California, Berkeley
>>
>>u n z i p m y a d d r e s s t o s e n d e - m a i l
>
>
>


--
Phil Robyn [MS MVP]
Univ. of California, Berkeley

u n z i p m y a d d r e s s t o s e n d e - m a i l

On Thu, 17 Mar 2005 13:45:47 -0500, "TJT" <(E-Mail Removed)> wrote:

>I have a bat file in which I need to know the last node of a directory
>string. I know that I am not properly describing it so let me give an
>example...
>
>Assuming that I am executing a bat file from the directory path
> C:\TestPrograms\Version6\Release2
>
>I would like to be able to obtain the last node ("Release2"). I've tried
>everything but can't seem to get this to work.
>
>I tried something like the following
>SET FullPath=%CD%
>cd..
>SET PartPath=%CD%
>
>At this point
> FullPath=C:\TestPrograms\Version6\Release2
>and
> PartPath=C:\TestPrograms\Version6
>
>I tried executing the following to essentially change
>"C:\TestPrograms\Version6" to empty string but it didn't work as I had hoped
>SET LastNode = %FullPath:%PartPath=%
>
>Any help would be greatly appreciated.
>
>

@echo off
setlocal
call :lastnode "C:\TestPrograms\Version6\Release2"
@echo Last node is %lstn%
@echo Parent path is %prnt%
endlocal
goto :EOF
:lastnode
set lstn=%~n1
set prnt=%~dp1

Jerold Schulman
Windows Server MVP
JSI, Inc.
http://www.jsiinc.com

TJT wrote:
> Phil - Thanks for the reply.
>
> I tried executing the following test batch....
> @echo off
> SET FullPath=C:\TestPrograms\Version6\Release2
> SET PartPath=C:\TestPrograms\Version6
>
> echo FullPath=%FullPath%
> echo PartPath=%PartPath%
>
> set LastNode=!FullPath:%PartPath%=!
> echo LastNode=%LastNode%
>
>
> I was hoping to get LastNode=Version6 but I am not getting it. Here's the
> output from the batch...
> FullPath=C:\TestPrograms\Version6\Release2
> PartPath=C:\TestPrograms\Version6
> LastNode=!FullPath:C:\TestPrograms\Version6=!
>
> Thanks,
> Tom

'Version6' is the *next*-to-last node.

C:\cmd>demo\NexttoLastNode
Next to last node is Version6

C:\cmd>rlist demo\NexttoLastNode.cmd
=====begin C:\cmd\demo\NexttoLastNode.cmd ====================
01. @echo off
02. setlocal
03. SET FullPath=C:\TestPrograms\Version6\Release2
04. set first=
05. set rest=
06. :loop
07. for /f "tokens=1* delims=\" %%a in (
08. 'echo %FullPath%'
09. ) do set first=%%a&set FullPath=%%b
10. if defined FullPath (
11. set next_to_last=%first%
12. goto :loop
13. )
14. echo/Next to last node is %next_to_last%
=====end C:\cmd\demo\NexttoLastNode.cmd ====================

> "Phil Robyn" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
>
>>TJT wrote:
>>
>>>I have a bat file in which I need to know the last node of a directory
>>>string. I know that I am not properly describing it so let me give an
>>>example...
>>>
>>>Assuming that I am executing a bat file from the directory path
>>> C:\TestPrograms\Version6\Release2
>>>
>>>I would like to be able to obtain the last node ("Release2"). I've
>
> tried
>
>>>everything but can't seem to get this to work.
>>>
>>>I tried something like the following
>>>SET FullPath=%CD%
>>>cd..
>>>SET PartPath=%CD%
>>>
>>>At this point
>>> FullPath=C:\TestPrograms\Version6\Release2
>>>and
>>> PartPath=C:\TestPrograms\Version6
>>>
>>>I tried executing the following to essentially change
>>>"C:\TestPrograms\Version6" to empty string but it didn't work as I had
>
> hoped
>
>>>SET LastNode = %FullPath:%PartPath=%
>>>
>>>Any help would be greatly appreciated.
>>>
>>>
>>>
>>
>>If you have Win2000 or WinXP, you can use delayed expansion:
>>
>> set LastNode=!FullPath:%PartPath%=!
>>
>>If you have NT4.0:
>>
>> call set LastNode=%%FullPath:%PartPath%=%%
>>
>>--
>>Phil Robyn
>>Univ. of California, Berkeley
>>
>>u n z i p m y a d d r e s s t o s e n d e - m a i l
>
>
>


--
Phil Robyn
Univ. of California, Berkeley

u n z i p m y a d d r e s s t o s e n d e - m a i l

I'm sorry Phil - I cut and pasted the wrong value. My fingers are a few
steps ahead of my brain. Sorry for the confusion.

I am not looking for Version6 (next-to-last node), I am actually looking for
Release2.

Thanks,
Tom
"Phil Robyn" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> TJT wrote:
> > Phil - Thanks for the reply.
> >
> > I tried executing the following test batch....
> > @echo off
> > SET FullPath=C:\TestPrograms\Version6\Release2
> > SET PartPath=C:\TestPrograms\Version6
> >
> > echo FullPath=%FullPath%
> > echo PartPath=%PartPath%
> >
> > set LastNode=!FullPath:%PartPath%=!
> > echo LastNode=%LastNode%
> >
> >
> > I was hoping to get LastNode=Version6 but I am not getting it. Here's
the
> > output from the batch...
> > FullPath=C:\TestPrograms\Version6\Release2
> > PartPath=C:\TestPrograms\Version6
> > LastNode=!FullPath:C:\TestPrograms\Version6=!
> >
> > Thanks,
> > Tom
>
> 'Version6' is the *next*-to-last node.
>
> C:\cmd>demo\NexttoLastNode
> Next to last node is Version6
>
> C:\cmd>rlist demo\NexttoLastNode.cmd
> =====begin C:\cmd\demo\NexttoLastNode.cmd ====================
> 01. @echo off
> 02. setlocal
> 03. SET FullPath=C:\TestPrograms\Version6\Release2
> 04. set first=
> 05. set rest=
> 06. :loop
> 07. for /f "tokens=1* delims=\" %%a in (
> 08. 'echo %FullPath%'
> 09. ) do set first=%%a&set FullPath=%%b
> 10. if defined FullPath (
> 11. set next_to_last=%first%
> 12. goto :loop
> 13. )
> 14. echo/Next to last node is %next_to_last%
> =====end C:\cmd\demo\NexttoLastNode.cmd ====================
>
> > "Phil Robyn" <(E-Mail Removed)> wrote in message
> > news:(E-Mail Removed)...
> >
> >>TJT wrote:
> >>
> >>>I have a bat file in which I need to know the last node of a directory
> >>>string. I know that I am not properly describing it so let me give an
> >>>example...
> >>>
> >>>Assuming that I am executing a bat file from the directory path
> >>> C:\TestPrograms\Version6\Release2
> >>>
> >>>I would like to be able to obtain the last node ("Release2"). I've
> >
> > tried
> >
> >>>everything but can't seem to get this to work.
> >>>
> >>>I tried something like the following
> >>>SET FullPath=%CD%
> >>>cd..
> >>>SET PartPath=%CD%
> >>>
> >>>At this point
> >>> FullPath=C:\TestPrograms\Version6\Release2
> >>>and
> >>> PartPath=C:\TestPrograms\Version6
> >>>
> >>>I tried executing the following to essentially change
> >>>"C:\TestPrograms\Version6" to empty string but it didn't work as I had
> >
> > hoped
> >
> >>>SET LastNode = %FullPath:%PartPath=%
> >>>
> >>>Any help would be greatly appreciated.
> >>>
> >>>
> >>>
> >>
> >>If you have Win2000 or WinXP, you can use delayed expansion:
> >>
> >> set LastNode=!FullPath:%PartPath%=!
> >>
> >>If you have NT4.0:
> >>
> >> call set LastNode=%%FullPath:%PartPath%=%%
> >>
> >>--
> >>Phil Robyn
> >>Univ. of California, Berkeley
> >>
> >>u n z i p m y a d d r e s s t o s e n d e - m a i l
> >
> >
> >
>
>
> --
> Phil Robyn
> Univ. of California, Berkeley
>
> u n z i p m y a d d r e s s t o s e n d e - m a i l

"Jerold Schulman" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> On Thu, 17 Mar 2005 13:45:47 -0500, "TJT" <(E-Mail Removed)> wrote:
>
> >I have a bat file in which I need to know the last node of a directory
> >string. I know that I am not properly describing it so let me give an
> >example...
> >
> >Assuming that I am executing a bat file from the directory path
> > C:\TestPrograms\Version6\Release2
> >
> >I would like to be able to obtain the last node ("Release2"). I've tried
> >everything but can't seem to get this to work.
> >
> >I tried something like the following
> >SET FullPath=%CD%
> >cd..
> >SET PartPath=%CD%
> >
> >At this point
> > FullPath=C:\TestPrograms\Version6\Release2
> >and
> > PartPath=C:\TestPrograms\Version6
> >
> >I tried executing the following to essentially change
> >"C:\TestPrograms\Version6" to empty string but it didn't work as I had
hoped
> >SET LastNode = %FullPath:%PartPath=%
> >
> >Any help would be greatly appreciated.
> >
> >
>
> @echo off
> setlocal
> call :lastnode "C:\TestPrograms\Version6\Release2"
> @echo Last node is %lstn%
> @echo Parent path is %prnt%
> endlocal
> goto :EOF
> :lastnode
> set lstn=%~n1
> set prnt=%~dp1

Finally, the straight-forward answer. Considering that folder names may have
extensions, however, shouldn't that second last line actually be:

set lstn=%~nx1

Also lost in the verbiage might have been how to actually get the path
needed:

> @echo off
> setlocal
echo/for folder containing batch file:
call:lastnode "%~dp0"
> @echo Last node is %lstn%
> @echo Parent path is %prnt%
echo/for current directory:
call:lastnode "%cd%"
> @echo Last node is %lstn%
> @echo Parent path is %prnt%
> endlocal
> goto :EOF
> :lastnode
set lstn=%~nx1
> set prnt=%~dp1


/Al

On Thu, 17 Mar 2005 22:08:44 -0700, "Al Dunbar [MS-MVP]" <alan-no-drub-(E-Mail Removed)> wrote:

>
>"Jerold Schulman" <(E-Mail Removed)> wrote in message
>news:(E-Mail Removed)...
>> On Thu, 17 Mar 2005 13:45:47 -0500, "TJT" <(E-Mail Removed)> wrote:
>>
>> >I have a bat file in which I need to know the last node of a directory
>> >string. I know that I am not properly describing it so let me give an
>> >example...
>> >
>> >Assuming that I am executing a bat file from the directory path
>> > C:\TestPrograms\Version6\Release2
>> >
>> >I would like to be able to obtain the last node ("Release2"). I've tried
>> >everything but can't seem to get this to work.
>> >
>> >I tried something like the following
>> >SET FullPath=%CD%
>> >cd..
>> >SET PartPath=%CD%
>> >
>> >At this point
>> > FullPath=C:\TestPrograms\Version6\Release2
>> >and
>> > PartPath=C:\TestPrograms\Version6
>> >
>> >I tried executing the following to essentially change
>> >"C:\TestPrograms\Version6" to empty string but it didn't work as I had
>hoped
>> >SET LastNode = %FullPath:%PartPath=%
>> >
>> >Any help would be greatly appreciated.
>> >
>> >
>>
>> @echo off
>> setlocal
>> call :lastnode "C:\TestPrograms\Version6\Release2"
>> @echo Last node is %lstn%
>> @echo Parent path is %prnt%
>> endlocal
>> goto :EOF
>> :lastnode
>> set lstn=%~n1
>> set prnt=%~dp1
>
>Finally, the straight-forward answer. Considering that folder names may have
>extensions, however, shouldn't that second last line actually be:
>
> set lstn=%~nx1
>
>Also lost in the verbiage might have been how to actually get the path
>needed:
>
>> @echo off
>> setlocal
> echo/for folder containing batch file:
> call:lastnode "%~dp0"
>> @echo Last node is %lstn%
>> @echo Parent path is %prnt%
> echo/for current directory:
> call:lastnode "%cd%"
>> @echo Last node is %lstn%
>> @echo Parent path is %prnt%
>> endlocal
>> goto :EOF
>> :lastnode
> set lstn=%~nx1
>> set prnt=%~dp1
>
>
>/Al
>

Yes, in the general case set lstn=%~nx1 is correct.



Jerold Schulman
Windows Server MVP
JSI, Inc.
http://www.jsiinc.com