I definitely don't, Rick
;-)
On 9 Kwi, 10:19, "Rick Rothstein"
<rick.newsNO.S...@NO.SPAMverizon.net> wrote:
> I'm glad you liked it. We can actually shorten it by two character by
> removing the one unnecessary set of parentheses...
>
> =SUMPRODUCT(D1:K1*(2-(D1:K1="")))
>
> And, if you don't mind array-entered** formulas, we can save another 7
> characters using this array-entered** formula...
>
> =SUM(D1:K1*(2-(D1:K1="")))
>
> **commit formula using Ctrl+Shift+Enter and not Enter by itself
>
> --
> Rick (MVP - Excel)
>
> "Jarek Kujawa" <bli...@gazeta.pl> wrote in message
>
> news:7aa56e8f-0452-48e8-872d-(E-Mail Removed)...
>
>
>
> > cute
>
> > I like that one
>
> > ;-)
>
> > On 9 Kwi, 09:52, "Rick Rothstein"
> > <rick.newsNO.S...@NO.SPAMverizon.net> wrote:
> >> Try this formula...
>
> >> =SUMPRODUCT((D1:K1)*(2-(D1:K1="")))
>
> >> --
> >> Rick (MVP - Excel)
>
> >> "jkrons" <j...@knord.dk> wrote in message
>
> >>news:94ed1f03-50cb-43dd-8c74-(E-Mail Removed)....
>
> >> > I have a number of cells in a row, D3:K3 (actually the row will
> >> > contain columns up to FZ). These cells can either contain a number o4r
> >> > be empty. An example could be
>
> >> > D Â*E Â*F Â*G Â*H Â*I Â*J Â*K
> >> > 2 Â*4 Â* 7 Â* 2 Â*- Â* 2 Â*- Â*7
>
> >> > The "-" indicates an empty cell.
>
> >> > Now what I need is a formula, that takes the sum of all the cells and
> >> > multiply the sum by by 2 (the easy part :-)), and divides it with the
> >> > number of cells, multiplied by two, if the cell is not empty and
> >> > multiplied by 1 if the cell isempty.
>
> >> > In the above example the multiplied by 2 sum is 48. And this should be
> >> > divided by 14 as there are 6 values (mulitplied by two) and two empty
> >> > cells. COUNT will count the cells with content
>
> >> > Jan- Ukryj cytowany tekst -
>
> >> - Poka¿ cytowany tekst -- Ukryj cytowany tekst -
>
> - Pokaż cytowany tekst -
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