Try
<div style="position: absolute; width: 100px; height: 30px; z-index: 3;
left: 101px; top: 306px" id="LayerShowCotopaxi"> <img border="0"
src="images/Index_Button/leaf_Cotop.gif" width="98"
height="33" onmouseout="FP_changePropRestore()"
onmouseover="FP_changeProp(/*id*/'LayerShowCotopaxi0',1,'style.visibility','visible');
FP_changeProp(/*id*/'cellID',1,'style.background-image','url(/images/newbackground.jpg)');"></div>
Not tested.
--
Ron Symonds - Microsoft MVP (FrontPage)
Reply only to group - emails will be deleted unread.
http://www.rxs-enterprises.org/fp
"Wayne-I-M" <(E-Mail Removed)> wrote in message
news:AE39DAC4-7A66-4B43-A20F-(E-Mail Removed):
> Hi
>
> Is it possible to change the background picture of a cell with the mouse is
> over another graphic. I could just add another layer and have that shown but
> this seems (to my non-expert eyes) to be a little too much.
>
>
> eg. I have this that shows a layer when you hover the mouse.
>
> <div style="position: absolute; width: 100px; height: 30px; z-index: 3;
> left: 101px; top: 306px" id="LayerShowCotopaxi">
> <img border="0" src="images/Index_Button/leaf_Cotop.gif" width="98"
> height="33" onmouseout="FP_changePropRestore()"
> onmouseover="FP_changeProp(/*id*/'LayerShowCotopaxi0',1,'style.visibility','visible')"></div>
>
> Can I add to this to change the background image in another cell at the same
> time
>
> Thanks you
>
>
> --
> Wayne
> Manchester, England.