I am having an issue trying to use a binary reader. In the following case I
would like to have the value 66 and 3 returned respectivly but I am getting
large number since the reader is reading in littleendian format.

Here is my code

Dim Buffer() As Byte = New Byte() {&H0, &H0, &H0, &H42, &H0,
&H0, &H0, &H3}
Dim ms As New IO.MemoryStream(Buffer)
Dim br As New IO.BinaryReader(ms,
Text.Encoding.BigEndianUnicode)
Console.WriteLine("Message Length = " & br.ReadInt32())
Console.WriteLine("Message Type = " & br.ReadInt32())

This generates

Message Length = 1107296256
Message Type = 50331648



Does anyone know of an easy way to accomplish this or so I have to write my
own encoder?



Thanks
Craig J. Klinker
IntraNext Systems

Craig Klinker <(E-Mail Removed)> wrote:
> I am having an issue trying to use a binary reader. In the following case I
> would like to have the value 66 and 3 returned respectivly but I am getting
> large number since the reader is reading in littleendian format.
>
> Here is my code
>
> Dim Buffer() As Byte = New Byte() {&H0, &H0, &H0, &H42, &H0,
> &H0, &H0, &H3}
> Dim ms As New IO.MemoryStream(Buffer)
> Dim br As New IO.BinaryReader(ms,
> Text.Encoding.BigEndianUnicode)
> Console.WriteLine("Message Length = " & br.ReadInt32())
> Console.WriteLine("Message Type = " & br.ReadInt32())
>
> This generates
>
> Message Length = 1107296256
> Message Type = 50331648
>
>
>
> Does anyone know of an easy way to accomplish this or so I have to write my
> own encoder?

Basically you need a version of BinaryReader which allows you to
specify the endianness. I've considered writing such a class before -
if you'd like me to do it for you, just let me know.

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

Thanks for the reply. I can write this but I thought I would check if
something already existed before doing it myself.

"Jon Skeet [C# MVP]" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Craig Klinker <(E-Mail Removed)> wrote:
> > I am having an issue trying to use a binary reader. In the following
case I
> > would like to have the value 66 and 3 returned respectivly but I am
getting
> > large number since the reader is reading in littleendian format.
> >
> > Here is my code
> >
> > Dim Buffer() As Byte = New Byte() {&H0, &H0, &H0, &H42, &H0,
> > &H0, &H0, &H3}
> > Dim ms As New IO.MemoryStream(Buffer)
> > Dim br As New IO.BinaryReader(ms,
> > Text.Encoding.BigEndianUnicode)
> > Console.WriteLine("Message Length = " & br.ReadInt32())
> > Console.WriteLine("Message Type = " & br.ReadInt32())
> >
> > This generates
> >
> > Message Length = 1107296256
> > Message Type = 50331648
> >
> >
> >
> > Does anyone know of an easy way to accomplish this or so I have to write
my
> > own encoder?
>
> Basically you need a version of BinaryReader which allows you to
> specify the endianness. I've considered writing such a class before -
> if you'd like me to do it for you, just let me know.
>
> --
> Jon Skeet - <(E-Mail Removed)>
> http://www.pobox.com/~skeet
> If replying to the group, please do not mail me too