I am reading bytes from a serial port which come from a device which uses
the Big-Endian storage format. My question is, can I use the
BitConverter.ToDouble(bytearray, position) method to convert those bytes to
a double? In other words, will the system take into account that the byte
order needs to be swapped?

Conversely, I need to write longs and double to the serial device in
Big-Endian format. How would I do that?

Thanks,

Chris

"Chris P" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> I am reading bytes from a serial port which come from a device which uses
> the Big-Endian storage format. My question is, can I use the
> BitConverter.ToDouble(bytearray, position) method to convert those bytes
to
> a double? In other words, will the system take into account that the byte
> order needs to be swapped?
>
> Conversely, I need to write longs and double to the serial device in
> Big-Endian format. How would I do that?
>
>

BitConverter will not be able to swap bytes for you. You will need to do it
yourself and then use BitConverter (or, if you are writing to the port, get
bytes using BitConverter and then swap the byte order). You can P/Invoke
htonl and ntohl but that is no help with doubles

Chris,

You should be able to use the BitConverter to convert your doubles to longs
through byte arrays (ex: long l =
BitConverter.ToInt64(BitConverter.GetBytes(double)); ) and then convert them
between host and network order using IPAddress.HostToNetworkOrder() and
IPAddress.NetworkToHostOrder().

Hope this helps,
David Kline
Microsoft .NET Compact Framework

This posting is provided "AS IS" with no warranties, and confers no rights.


"Chris P" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> I am reading bytes from a serial port which come from a device which uses
> the Big-Endian storage format. My question is, can I use the
> BitConverter.ToDouble(bytearray, position) method to convert those bytes
to
> a double? In other words, will the system take into account that the byte
> order needs to be swapped?
>
> Conversely, I need to write longs and double to the serial device in
> Big-Endian format. How would I do that?
>
> Thanks,
>
> Chris
>
>

David,

Thank You.

Chris
"David Kline [msft]" <(E-Mail Removed)> wrote in message
news:gNYsb.144067$275.440806@attbi_s53...
> Chris,
>
> You should be able to use the BitConverter to convert your doubles to
longs
> through byte arrays (ex: long l =
> BitConverter.ToInt64(BitConverter.GetBytes(double)); ) and then convert
them
> between host and network order using IPAddress.HostToNetworkOrder() and
> IPAddress.NetworkToHostOrder().
>
> Hope this helps,
> David Kline
> Microsoft .NET Compact Framework
>
> This posting is provided "AS IS" with no warranties, and confers no
rights.
>
>
> "Chris P" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
> > I am reading bytes from a serial port which come from a device which
uses
> > the Big-Endian storage format. My question is, can I use the
> > BitConverter.ToDouble(bytearray, position) method to convert those bytes
> to
> > a double? In other words, will the system take into account that the
byte
> > order needs to be swapped?
> >
> > Conversely, I need to write longs and double to the serial device in
> > Big-Endian format. How would I do that?
> >
> > Thanks,
> >
> > Chris
> >
> >
>
>