In A1

1 I entered the numbers 10, 5, 2, 1 representing the weighting for
integers 1,2,3,4.
Thus I want 1 to be 10 times more likely than 4, etc
In A3 I entered =RANDBETWEEN(1,SUM($A$!:$D$1)
In B3 I used the formula
=IF(A4<=$A$1,1,IF(A4<=SUM($A$1:$B$1),2,IF(A4<=SUM($A$1:$C$1),3,4)))
I copied these two down to row 5003 to get 5000 random numbers
Note that RANDBETWEEN need the Analysis Toolpac in pre-2007 versions of
Excel
I used the Frequency function to find I had this distribution
1 2827 10.66792453
2 1362 5.139622642
3 546 2.060377358
4 265 1
So I have 2827 ones and one is 10.7 more frequent than 4
Hit F9 and I get
1 2855 10.93869732
2 1325 5.076628352
3 559 2.141762452
4 261 1
and so on
Any help?
best wishes
--
Bernard V Liengme
Microsoft Excel MVP
http://people.stfx.ca/bliengme
remove caps from email
"plh" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Hi Gurus,
> What I want to do is similar to the use of the Rnd() function but I want
> to bias
> the results. In my case I am obtaining numbers from 1 to 4 using
> Int((uB - lB + 1) * Rnd + lB)
> Where uB = 4 and lB = 1, but I want to skew the outcome so that 1 is more
> probable that 2 which is more probable than 3 etc., with the probability
> values
> yet to be determined.
> Thank You,
> -plh
>
>
> --
> Where are we going and why am I in this HAND BASKET??