I use the +Today() in cell L23 to automatically update the date and wanted
the day to correspond to a preset colour that I was hoping the conditional
macro would maintain.
I just want the day to change automatically and the colour to follow suite.
No manual input.
Hope this helps you help me
Many thanks for the patience, I appreciate I'm way out of my depth and this
is a simple thing but....its a learning curve, well step actually
Thanks again.
Andrew
"Dave Peterson" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Your routine is checking two cells (L22 and L23) for changes made by the
> user--not changes made by calculation.
>
> Do they both contain formulas? Or do you just expect the user to change
> one of
> the cells--and why wouldn't the user just type in a date instead of using
> the
> formula =today().
>
> I guess I don't understand enough to help. (Maybe enough to break what
> you're
> really doing, but not enough to help.)
>
> And without knowing too much, you could always just plop that formula into
> the
> cell when the workbook opens.
>
> Behind thisWorkbook (not behind the worksheet and not in a general
> module).
>
> Option Explicit
> Sub Workbook_Open()
> me.worksheets("someworksheetnamehere").range("L22").formula = "=Today()"
> end sub
>
> =========
> I used L22--I don't have any idea if that's good or bad, though.
>
> "@Homeonthecouch" wrote:
>>
>> Private Sub Worksheet_Change(ByVal Target As Range)
>>
>> If Target.Cells.Count > 1 Then Exit Sub
>> If Intersect(Target, Range("L22:L23")) Is Nothing Then Exit Sub
>>
>> With Target
>> Select Case Weekday(.Value)
>> Case Is = vbMonday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 7
>> Case Is = vbTuesday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 44
>> Case Is = vbWednesday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 6
>> Case Is = vbThursday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 4
>> Case Is = vbFriday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 8
>> Case Is = vbSaturday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 33
>> Case Is = vbSunday: .Offset(-1, 0).Resize(2,
>> 1).Interior.ColorIndex = 18
>> End Select
>> End With
>>
>> End Sub
>>
>> So I would assume no?
>>
>> I am totally inexperienced with VBA and have no real idea what I am
>> doing, I
>> am learning the methods I find on the net and in these help groups.
>> Do I need to change the Worksheet_Change to Worksheet_Calculate?
>> The cell updates perfectly when the workbook is opened but the colour
>> remains the same as the last time the cell was updated when enter was
>> hit.
>>
>> --
>> Help and patience is as always appreciated
>> Thank You
>>
>> Andrew
>>
>> "Dave Peterson" <(E-Mail Removed)> wrote in message
>> news:(E-Mail Removed)...
>> > Are you using the worksheet_calculate event? That event recalced for
>> > me
>> > when I
>> > opened a workbook with =today() in a cell (xl2003).
>> >
>> > If you're not using that event, maybe you could call your macro from
>> > the
>> > Workbook_Open event or the Auto_Open procedure?
>> >
>> >
>> >
>> >
>> >
>> > "@Homeonthecouch" wrote:
>> >>
>> >> Hi again,
>> >> I have just noticed that when I open the spreadsheet the cell with the
>> >> =today() command automatically updates but the macro that is dependant
>> >> on
>> >> the answer does not update.
>> >> I have tried to use refresh F9 but that doesn't work. I can go into
>> >> the
>> >> cell
>> >> and hit enter and that then refreshes the colour assigned to the day.
>> >> Is there a way of doing this when the spreadsheet opens up? Or is that
>> >> not
>> >> advisable?
>> >>
>> >> Andrew
>> >
>> > --
>> >
>> > Dave Peterson
>
> --
>
> Dave Peterson