Hi,

I want to use an array str, while each array element str[i]
is an array of chars of fixed length, say 40;

The best way to handle this in C# is StringBuilder I guess,
but as legacy C++ code must communicate with my C# app, I
prefer only low-level primitive types, so chars here.

Of course, char [] str = new char[40]; will create an array
of 40 chars for me, but that's not what I want.

I need something like :

for (int i=0;i<50;i++)
{
char [] str[i] = new char[40];
}
I guess, but how to dimension the array str itself. By
using char [] [] .... ????

Confused with the double dimensions, one for the array
lenght of str , and one for the number of chars in each
array element ...

Some help would be nice.

Thanks,
Peter

Peter wrote:
> Hi,
>
> I want to use an array str, while each array element str[i]
> is an array of chars of fixed length, say 40;
>
> The best way to handle this in C# is StringBuilder I guess,
> but as legacy C++ code must communicate with my C# app, I
> prefer only low-level primitive types, so chars here.
>
> Of course, char [] str = new char[40]; will create an array
> of 40 chars for me, but that's not what I want.
>
> I need something like :
>
> for (int i=0;i<50;i++)
> {
> char [] str[i] = new char[40];
> }
> I guess, but how to dimension the array str itself. By
> using char [] [] .... ????
>
> Confused with the double dimensions, one for the array
> lenght of str , and one for the number of chars in each
> array element ...
>
> Some help would be nice.
>
> Thanks,
> Peter
>

Do a search for multidimensional arrays in the MSDN library.

You want something like:
char[,] myArray = new char[10,40];

Peter wrote:
> Hi,
>
> I want to use an array str, while each array element str[i]
> is an array of chars of fixed length, say 40;
> (abridged)
> I need something like :
>
> for (int i=0;i<50;i++)
> {
> char [] str[i] = new char[40];
> }
You've got two options. If every char array is the same length, eg. 40.
You can use a multidimensional array:
char[,] str=new char[40,40];

If the arrays aren't the same length, you must use a jagged array which
is an array-of-arrays.
char[][] str=new char[40][];
for (int i=0; i<40;i++) {
str[i]=new string[i*2];
}

Anders Norås
http://dotnetjunkies.com/weblog/anoras/

Peter <(E-Mail Removed)> wrote:
> I want to use an array str, while each array element str[i]
> is an array of chars of fixed length, say 40;
>
> The best way to handle this in C# is StringBuilder I guess,
> but as legacy C++ code must communicate with my C# app, I
> prefer only low-level primitive types, so chars here.
>
> Of course, char [] str = new char[40]; will create an array
> of 40 chars for me, but that's not what I want.
>
> I need something like :
>
> for (int i=0;i<50;i++)
> {
> char [] str[i] = new char[40];
> }
> I guess, but how to dimension the array str itself. By
> using char [] [] .... ????
>
> Confused with the double dimensions, one for the array
> lenght of str , and one for the number of chars in each
> array element ...

char[][] str = new char[50][];

for (int i=0; i < 50; i++)
{
str[i] = new char[40];
}

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

Jon,

I was waiting for your answer because I thought there should be something
else, luckily for my self-coinfidence you did not show that as well. (And
still I am not sure)

:-)

Cor