I'm changed 'A.Line_id = Value(B.Reference_3)' to be 'TRIM(A.Line_id) =
ValueB.Reference_3' it's work already!
SQL_Text = "SELECT A.Line_id, B.Reference_3 " & _
vbCrLf & "FROM A LEFT JOIN B ON TRIM(A.Line_id) =
B.Reference_3"
--
Thanks,
Sakol
"Sakol" wrote:
> Did i use the wrong convension function "Value(B.Reference_3)" ?
> --
> Sakol
>
>
> "Sakol" wrote:
>
> > I'm still got message
> >
> > Run_time error '-2147217900 (80040e14)':
> > [Microsoft][ODBC driver for Oracle][Oracle] ORA-00904:
> > "B"."REFERENCE_3": Invalid indentifier
> >
> > What can i do next for fix it?
> > --
> > Sakol
> >
> >
> > "galimi" wrote:
> >
> > > Sakol,
> > >
> > > Following is an example
> > >
> > > strMessage = "I would like to put a carriage return/life feed" & _
> > > vbCrLf & "before the previous line"
> > >
> > > MsgBox strMessage
> > > --
> > > http://HelpExcel.com
> > > (E-Mail Removed)
> > >
> > >
> > >
> > > "Sakol" wrote:
> > >
> > > > I try to set relation between A.Line_id field type = Double vs. B.Reference_3
> > > > field type = String, it's not work.
> > > > Here the Sample:-
> > > > strseparate = Chr(13) & " " & Chr(10)
> > > > SQL_Text = "SELECT A.Line_id, B.Reference_3 " & strseparate & _
> > > > "FROM A LEFT JOIN B ON A.Line_id = Value(B.Reference_3)"
> > > >
> > > > Anybody can help would be appreciate very much
> > > >
> > > > --
> > > > Sakol