// Example

public struct SomeData
{
public int X;
public int Y;

public SomeData(int x, int y)
{ ... }
}

....

Hashtable table = new Hashtable();
SomeData sd = new SomeData(1, 2)
table.Add(1, sd);


// this of course does not work, cause is passed by value
// but is there a way, or I need a class to encapsulate data types (stupid
solution)

((SomeData)table[1]).X = 2;

Mitja Semolic <(E-Mail Removed)> wrote:
> // Example
>
> public struct SomeData
> {
> public int X;
> public int Y;
>
> public SomeData(int x, int y)
> { ... }
> }
>
> ...
>
> Hashtable table = new Hashtable();
> SomeData sd = new SomeData(1, 2)
> table.Add(1, sd);
>
>
> // this of course does not work, cause is passed by value
> // but is there a way, or I need a class to encapsulate data types (stupid
> solution)
>
> ((SomeData)table[1]).X = 2;

Well, you can do:

SomeData sd = (SomeData)table[1];
sd.X=2;
table[1]=sd;

I would seriously suggest considering using a class instead though. I
find the number of times when it's a good idea to define my own value
types is very small indeed.

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too