Please not that when it gets to the numbers that begin with zero, excel will
treat it as a number and automatically drop the zero.
So "012" would end up being "12". One way that could fix this is to format
column B as text before you run this code.
Glad I could help.
Paul
--
"Allison" <(E-Mail Removed)> wrote in message
news:76CB2E0B-1D52-4E33-911C-(E-Mail Removed)...
> This worked great. Thank you very much.
>
> Allison
>
> "PCLIVE" wrote:
>
>> Probably other ways, but here's one:
>>
>> - Place A-Z in A1 to A26
>> - Place 0-9 in A27 to A36
>>
>> Then you can use this code.
>>
>> Sub test()
>>
>> For cOne = 1 To 36
>> myCell1 = Range("A" & cOne).Value
>> For cTwo = 1 To 36
>> myCell2 = myCell1 & Range("A" & cTwo).Value
>> For cThree = 1 To 36
>> myCell3 = myCell2 & Range("A" & cThree).Value
>> Range("B" & Range("B65536").End(xlUp).Row + 1).Value =
>> myCell3
>> Next cThree
>> Next cTwo
>> Next cOne
>>
>> End Sub
>>
>>
>> HTH,
>> Paul
>>
>> --
>>
>> "Allison" <(E-Mail Removed)> wrote in message
>> news:86B2A5E5-70F5-440A-9B5E-(E-Mail Removed)...
>> > Excel 2003 SP3
>> > Win XP SP2
>> >
>> > Is there a quick way to generate a list of all possible 3-character
>> > combinations using the alpha characters A-Z and the numbers 0-9?
>> >
>> >
>>
>>
>>
|