Hello.
I have an integer whose value varies from 0 to 9999.
I want to print it in a four-digit format.
Like,
0000
0001
0002
.....
9998
9999
I tried String.Format("{0:####}",val), but it didn't work. How can I do
this? Thanks.

Instead of: String.Format("{0:####}",val),

Try: val.ToString("0000")

Brendan

"Cat" wrote:

> Hello.
> I have an integer whose value varies from 0 to 9999.
> I want to print it in a four-digit format.
> Like,
> 0000
> 0001
> 0002
> .....
> 9998
> 9999
> I tried String.Format("{0:####}",val), but it didn't work. How can I do
> this? Thanks.
>
>

Cat <(E-Mail Removed)> wrote:
> I have an integer whose value varies from 0 to 9999.
> I want to print it in a four-digit format.
> Like,
> 0000
> 0001
> 0002
> ....
> 9998
> 9999
> I tried String.Format("{0:####}",val), but it didn't work. How can I do
> this? Thanks.

Try {0:0000} as the format string instead. Alternatively (and slightly
more compactly), you can call ToString directly on val:
val.ToString("0000")

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

"Cat" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Hello.
> I have an integer whose value varies from 0 to 9999.
> I want to print it in a four-digit format.
> Like,
> 0000
> 0001
> 0002
> ....
> 9998
> 9999
> I tried String.Format("{0:####}",val), but it didn't work. How can I do
> this? Thanks.
>

String.Format("{0:d4}",val);

Bill

> I tried String.Format("{0:####}",val), but it didn't work. How can I
do
> this? Thanks.

String.PadLeft(4, '0')

--
Chris Parkinson